Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1. 2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube? 1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2. Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3. Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen 2SO 2 + O 2 → 2SO 3 1cm 3 of O 2 = 2cm 3 20cm 3 of O 2 = 2 x 20 = 40cm 3
Copper tetraoxosulphate VI is a blue crystal solid if it contains water of crystallization(copper(II)tetraoxosulphate VI pentahydrate,CuSO 4 .5H 2 O). The anhydrous form is white. Copper(II)tetraoxosulphate VI is electrovalent compound and it is one of the soluble compounds of copper. Tests for Copper(II) tetraoxosulphate VI In qualitative analysis of any compound or substance, the basic idea is to identify the ions in the compound. That means, one has to know the unique reactions of compound which contains any of the ions to be analyzed, for example all chlorides react with acidified silver trioxonitrate to form white precipitate which is soluble in ammonia solution. In the case of copper (II)tetraoxosulphate VI, the two ions are copper ion,Cu 2+ and tetraoxosulphate VI ion or radical,SO 4 2- .These two ions have some unique reactions which differentiate them from other ions. How to Test for Copper ion in an unknown sample (copper sulphate) Copper ion can