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Application of Gay-Lussac’s Law of Combining Volumes

Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1.     2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube?   1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2.     Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3.     Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen    2SO 2 + O 2 → 2SO 3 1cm 3 of O 2 = 2cm 3 20cm 3 of O 2 = 2 x 20 = 40cm 3

How to Analylse the ions in Copper ( II) tetraoxosulphate VI)

  Copper   tetraoxosulphate VI is   a blue crystal solid if it contains water of crystallization(copper(II)tetraoxosulphate VI pentahydrate,CuSO 4 .5H 2 O). The anhydrous form is white. Copper(II)tetraoxosulphate VI is electrovalent compound and it is one of the soluble compounds of copper.         Tests for Copper(II) tetraoxosulphate VI In qualitative analysis of any compound or substance, the basic idea is to identify the ions in the compound. That means, one has to know the unique reactions of compound which contains any of the ions to be analyzed, for example all chlorides react with acidified silver trioxonitrate to form white precipitate which is soluble in ammonia solution.   In the case of copper (II)tetraoxosulphate VI, the two ions are copper ion,Cu 2+ and   tetraoxosulphate VI ion or radical,SO 4 2- .These two ions have some unique reactions which differentiate them from other ions. How to Test for Copper ion in an unknown sample (copper sulphate) Copper ion can

Mole, Molar mass and Molar Volume

                                                                                                              Mole A mole of any substance is the amount of that substance which contains many elementary particles as the number of atoms in 12 grams of carbon -12. These elementary particles can be atoms, ions, electrons, molecules etc. A mole is a unit used in measuring the amount of particles.     The number of particles in one mole of any substance is equal to 6.02 x 10 23 . This number is also known as Avogadro’s number.        Molar Mass This is the mass of one mole of any substance expressed in grams. It is also the formula mass which is the sum of all atomic masses of all atoms in a compound expressed in grams. Example question 1 Calculate the molar mass of the following substances i)                                sodium chloride ii)                              chlorine iii)                            Oxygen (Na=23, Cl =35.5, O=16   Solution     Sodiu

Qualitative Analysis of Ammonium Trioxocarbonate (IV)

              Ammonium trioxocarbonate(IV) is an electrovalent compound just like any other ammonium salts. As an electrovalent compound, it has NH + (ammonium ion) as the cation and CO 3 2- (trioxocarbonate IV ion or radical) as the anion.                          (NH 4 ) 2 CO 3   -------    2NH 4 + + CO 3 2- Ammonium trioxocarbonate IV is a white crystal salt and it is very soluble in water like all other ammonium salts. It decomposes on heating to produce ammonium, water and carbon (IV)oxide.                      (NH 4 + ) 2 CO 3   ----------   2NH 3(g) + H 2 O (I) + CO 2(g)          Test for the Cation in Ammonium Trioxocarbonate IV To test the unknown sample, put the sample into a boiling tube, add a base or alkali into the boiling tube and heat gently.   Note: All ammonium salts liberate ammonia when heated with base or alkali.         (NH 4 ) 2 CO 3(s) + 2NaOH (aq) ----------   Na 2 CO 3 (aq) + H 2 O (l) + 2NH 3(g) Test the gas liberated with damp li