Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1. 2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube? 1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2. Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3. Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen 2SO 2 + O 2 → 2SO 3 1cm 3 of O 2 = 2cm 3 20cm 3 of O 2 = 2 x 20 = 40cm 3
Question 1 A source of sound wave of frequency 660Hz emits waves of wavelength 0.12m in air at 40 o C. What is the velocity of sound wave in air at this temperature? What would be the wavelength of sound wave from the source in air at 70 o C? Answer Frequency = f = 660Hz Wavelength= λ = 0.12m Temperature = 40+273 = 313K Velocity of sound wave at 40 0 C V = fλ = 660 x0.12 =79.2m/s Wavelength of wave at 70 0 C Note: to find the wavelength, we must find the velocity of the sound wave at 70 0 C. Velocity of sound wave is directly proportional to the square root of its temperature in kelvin. V 1 /V 2 = √T 1 /√T 2 V 1 = 79.2m/s T 1 = 313K T 2 = 70 + 273 = 343K 79.2/V 2 = √313/√343 79.2 2 /(V 2 ) 2 = 313/343 313(V 2 ) 2 = 79.2 2 x 343= 2151515.52 (V 2 ) 2 = 2151515.52/313 (V 2 ) 2 = 6873.9 V 2 = √6873.9 = 82.9m/s Since V=fλ then 82.9 = 660 x λ .λ = 82.9/660 =0.13m Question II A sound wave of velocity 200m/s, calculate the