Abuja — The West African Examinations Council (WAEC) has postponed the full implementation of the computer-based test (CBT) format for the 2026 Senior School Certificate Examination (SSCE) until 2027, according to a statement released at the council’s 63rd annual meeting in Umuahia, Abia State. Hajia Binta Abdulkadir, Chairman of WAEC’s Nigeria National Committee, explained that the 2026 May/June edition will now serve as a pilot phase — allowing candidates to sit for either the traditional paper-and-pen test or the digital format. She emphasized that no student will be disadvantaged by the transition. The delay follows widespread concern over the readiness of many schools, particularly in rural areas, for full digital exams. Many institutions lack adequate computers, reliable electricity, internet connectivity, and trained personnel—factors WAEC and the Federal Ministry of Education say are essential for a successful rollout. To facilitate the switch, WAEC co...
Question 1 A source of sound wave of frequency 660Hz emits waves of wavelength 0.12m in air at 40 o C. What is the velocity of sound wave in air at this temperature? What would be the wavelength of sound wave from the source in air at 70 o C? Answer Frequency = f = 660Hz Wavelength= λ = 0.12m Temperature = 40+273 = 313K Velocity of sound wave at 40 0 C V = fλ = 660 x0.12 =79.2m/s Wavelength of wave at 70 0 C Note: to find the wavelength, we must find the velocity of the sound wave at 70 0 C. Velocity of sound wave is directly proportional to the square root of its temperature in kelvin. V 1 /V 2 = √T 1 /√T 2 V 1 = 79.2m/s T 1 = 313K T 2 = 70 + 273 = 343K 79.2/V 2 = √313/√343 79.2 2 /(V 2 ) 2 = 313/343 313(V 2 ) 2 = 79.2 2 x 343= 2151515.52 (V 2 ) 2 = 2151515.52/313 (V 2 ) 2 = 6873.9 V 2 = √6873.9 = 82.9m/s Since V=fλ then 82.9 = 660 x λ .λ = 82.9/660 =0.13m Question II A sound wave of v...