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Application of Gay-Lussac’s Law of Combining Volumes

Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1.     2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube?   1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2.     Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3.     Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen    2SO 2 + O 2 → 2SO 3...
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Laws of Logarithms

  Log (AB) = Log A + Log B

  Log (A/B) = Log A – Log B

  Log (Ax) = X Log A

                                          Example Question

Simple the following without using tables

1.    Log 16 ÷Log 4

2.    Log 24 – Log6÷ Log 16

                          Solution

1)   Log 16÷Log 4

 

= Log 2x2x2x2÷Log 2x2

 

= Log 24÷Log 22

= 4Log 2÷2Log2

= 2

2)   Log 24 – Log6÷ Log 16

 

                Solution

Log 24 – Log 6÷ Log 16

 

Log (8x3) – Log (2x3) ÷ Log (2x2x2x2)

 

Log (23x3) - Log (2x3) ÷ Log24

 

Log 23+Log3 – (Log2+Log3) ÷Log24

 

3Log2+Log3-Log2- Log3÷ 4Log2

 

2Log2÷ 4Log2

 

= 1/2

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Application of Gay-Lussac’s Law of Combining Volumes

Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1.     2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube?   1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2.     Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3.     Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen    2SO 2 + O 2 → 2SO 3...
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