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Application of Gay-Lussac’s Law of Combining Volumes

Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1.     2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube?   1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2.     Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3.     Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen    2SO 2 + O 2 → 2SO 3...
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Logarithm Theory 2

 

1.      Given that Log 2 = 0.30101, evaluate the following,

i)        Log 16

Ii)  Log 128

 

                       Solution

i)         Log 16

 

= Log 24

 

=   4 Log 2

Substitute 0.30101 to Log 2

 

4        (0.30101) = 1.20404

 

ii)      Log 128        

= log 27

=  7 Log 2

= 7 (0.30101)

= 2.10707

2.      Evaluate without any tables

3Log2 +Log20 – log1.6

               Solution

3Log2+Log20-Log 1.6

= Log23+Log20-Log16/10

= Log{8x20x10/16}

= Log 100

= Log 102

= 2Log10

= 2x1 =2

 

 

 

 

 

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Application of Gay-Lussac’s Law of Combining Volumes

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