The analysis requires a good knowledge of
the specific reactions of the ions with certain reagents, for example an
unknown solution which contains copper ions will give a deep blue solution with
excess ammonia solution.
Related post Qualitative analysis of copper(II)tetraoxosulphate VI
So what we are going do here is to identify
these ions using their specific reactions.
A
mixture of calcium chloride and iron (II) tetraoxosulphate (VI) will undergo a double
decomposition reaction to yield calcium tetraoxosulphate (VI) and iron (II)
chloride.
CaCl2 (aq) + FeSO4 (aq) ---------
FeCl2(aq) + CaSO4(s)
Since calcium tetraoxosulphate (VI) is
insoluble, iron(II)chloride can easily
be filtered off with filter paper or by any other means possible.
How
to identify the Cations in the mixture
Cations are positive charged ions. We have two
of these types of ions in the mixture which
·
Iron (II) ions
·
Calcium ions
How
to identify Iron (II) ions
An unknown solution or solid sample which
contains iron (II) ion will react positively to the following test below:
·
Test with sodium hydroxide solution
·
Test with ammonia solution
·
Test with potassium hexacyanoferrate
(III) solution
So, we are going to use these tests to identify
iron (II) ion
Test
with sodium hydroxide solution
Add distilled water into the solid sample of the
mixture and then filter with filter paper. Divide the filtrated into four
portions, to the first portion add sodium hydroxide solution, in drops and then
in excess. If the solution contains iron (II) ion dirty green precipitate will
be formed which will be insoluble in excess sodium hydroxide solution. This confirms
the present of iron (II) ion.
Test
with ammonia solution
To the second portion of the filtrate, add
aqueous ammonia, in drops and then in excess, if the unknown solution contains iron
(II) ion, pale green precipitate will but formed which is insoluble in excess aqueous
ammonia. This shows that iron (II) ion is present.
Test
with potassium hexacyanoferrate(III) solution
To the third portion of the filtrate, add
hexacyanoferrate (III) solution, if the unknown solution contains iron (II)
ion, a dark blue precipitate will be formed. This confirms iron (II) ion.
How
to identify calcium ion
Calcium ions can be identified by the following
tests:
·
Test with sodium hydroxide solution
·
Test with ammonia solution
·
Test with ammonium solution
ethanedioate solution
We are going to discuss the test with sodium hydroxide
because others have been discussed on our previous post.
Relatedpost: Qualitative analysis of ions in calcium trioxonitrate V
Test
with sodium hydroxide solution
To the residue, add dilute hydrochloric acid and
divide the solution into two portions. To the first portion, add sodium hydroxide
solution in drops and then in excess. A white precipitate formed which is
insoluble in excess sodium hydroxide solution confirms the present of calcium
ion.
How
to identify the anions in the unknown mixture
The two anions in the mixture are
·
Chloride ion
·
Tetraoxosulphate VI
How
to identify chloride ion
To the last portion of the filtrate, add silver
trioxonitrate V and then dilute trioxonitrate V acid. If the filtrate has
chloride ion, white precipitate will be formed which is insoluble in the dilute
acid and is decolourized when exposed to sunlight confirms chloride ion.
How
to identify tetraoxosulphate (VI) radical (ion)
To the second portion of solution produced from
the residue or make other solution by adding dilute hydrochloric acid to a
portion of the residue, then add barium chloride solution. If tetraoxosulphate
VI radical is present, white precipitate will be formed, this confirms
tetraoxosulphate (VI) radical.
Related post : How to analyse the ions in a mixture of copper sulphate and ammonium carbonate
Example question
J is a mixture of two inorganic compounds. Carry
out the tests on the table below, copy and complete the table
Test |
Observation |
Inference |
(a ) J plus distilled water, filter
and keep both the filtrate and residue |
|
J
is likely a mixture of soluble and insoluble compounds |
(b ) Divide the filtrate from (a)
above into three portions to the first portion add dilute sodium hydroxide solution
in drops and then excess |
Dirty
green precipitate forms which is insoluble in excess sodium hydroxide solution
|
|
(c )
to the second portion add ammonia solution, in drops and in excess |
|
Fe2+
confirms |
(
d) to the third portion add dilute
trioxonitrate V acid then silver trioxonitrate V solution |
White
precipitate forms which is decolourized on exposure to light |
|
(
e) to the residue add about 5 cm3
of dilute hydrochloric acid and divide into two portions |
|
Ag+
,Cu+ and Pb+
absent |
(
f) to the first portion from (e) above add sodium hydroxide solution
in drops and then in excess |
White
precipitate forms which is insoluble in excess sodium hydroxide solution |
|
(
g) to the second portion add
barium chloride solution |
|
SO42+
present |
Answers
Test |
Observation |
Inference |
(a ) J plus distilled water, filter
and keep both the filtrate and residue |
Partly soluble |
J is likely
a mixture of soluble and insoluble compounds |
(b ) Divide the filtrate from (a)
above into three portions to the first portion add dilute sodium hydroxide solution
in drops and then excess |
Dirty green
precipitate forms which is insoluble in excess sodium hydroxide solution |
Fe2+
present |
(c )
to the second portion add ammonia solution, in drops and in excess |
Pale green
precipitate forms and insoluble in excess aqueous ammonia |
Fe2+
confirms |
( d) to the third portion add dilute trioxonitrate
V acid then silver trioxonitrate V solution |
White precipitate
forms which is decolourized on exposure to light |
Chloride ions
confirm |
( e) to the residue add about 5 cm3
of dilute hydrochloric acid and divide into two portions |
Soluble |
Ag+
,Cu+ and Pb+
absent |
( f) to the first portion from (e) above add sodium hydroxide solution
in drops and then in excess |
White precipitate
forms which is insoluble in excess sodium hydroxide solution |
Ca+
present |
( g) to the second portion add barium
chloride solution |
White precipitate
forms |
SO42+
present |
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