Skip to main content

Application of Gay-Lussac’s Law of Combining Volumes

Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1.     2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube?   1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2.     Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3.     Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen    2SO 2 + O 2 → 2SO 3 1cm 3 of O 2 = 2cm 3 20cm 3 of O 2 = 2 x 20 = 40cm 3

Factors Affecting Rates of Chemical Reaction

 The collision theory shows that the rate of a chemical reaction depends on the frequency of the effective collisions between reactant particles. So any factor that can influence one or all following

·         The energy content of the particles

·         The frequency of the collision of the particles

·         The activation energy of the chemical reaction

Can also affect the rate of chemical rate and such factors are

·         Nature of reactants

·         Concentration / pressure(for gas) of the reactants

·         Surface area of reactants

·         Temperature of reaction mixture

·         Presence of light

·         Presence of catalyst

Nature of Reactants: The rate of reaction is affected by the chemical nature of the reactants because the energy content of different substances is not the same. For example, zinc reacts very fast with dilute hydrochloric acid to liberate hydrogen while gold does not show any sign of reaction.

Concentration of reactants: The frequency of collision increases with an increase in concentration, for gas, an increase in pressure increases the frequency of collision, while the decrease in concentration or pressure (for gas) decreases the frequency of collision of the reactant particles.

The surface area of the reactants: powdered marble chips react faster with dilute hydrochloric acid than granules. This is because the powdered marble chips have increased surface area in contact with the acid.

Temperature: Reactions are faster at high temperatures and slower at low temperatures. The increase in temperature of a system can lead to an increase in the rate of chemical reaction in two ways;

·         By increasing the energies of particles more than or equal to the activation energy

·         By increasing the average speed of all the reactant particles due to increased kinetic energy

These ways increase the number of effective collisions and help the reaction to be faster.

Light: Photochemical reaction like the reaction between hydrogen and chlorine is explosive in the presence of bright sunlight but negligible in the absence of light.

Catalyst: This is a substance that can change the rate of a chemical reaction without undergoing any change at the end of the reaction. Some catalysts can promote the rate of response while some retard the reaction. 

Rate of Chemical Reaction

 

Comments

Popular posts from this blog

Application of Gay-Lussac’s Law of Combining Volumes

Gay Lussac’s of combining volumes states that gases react in simple ratio with one another and to volumes of the products provided that temperature and pressure remain constant. In this article, you will understand how to apply this law in calculation by studying the following examples below: 1.     2H 2 + O 2 → H 2 O In the reaction above, what volume of hydrogen would be left over when 300cm 3 of oxygen and hydrogen are exploded in a sealed tube?   1cm 3 of oxygen = 2cm 3 of hydrogen 300cm 3 of oxygen = 2 x 300 = 600cm 3 Volume of left over = 1000 – 600 = 400cm 3 2.     Calculate the volume of carbon (II) oxide required to react with 40cm 3 of oxygen. 2CO + O 2 → 2CO 2 1cm 3 of oxygen = 2cm 3 of CO 40cm 3 of oxygen = 2 x 40 = 80cm 3 3.     Calculate the volume of residual gases that would be produced when 100cm 3 of sulphur (IV) oxide reacts with 20cm 3 of oxygen    2SO 2 + O 2 → 2SO 3 1cm 3 of O 2 = 2cm 3 20cm 3 of O 2 = 2 x 20 = 40cm 3

Qualitative Analysis of inorganic Compound

  This is a type analysis which involves the identification of the ions ( cation and anion) in a given inorganic substance. Thus, Qualitative analysis deals with the identification of the compound. To effectively identify the ions, it is necessary to be able to observe the presence of any chemical reaction which is normally recognized by ·         Colour change ·         Evolution of gas ·         Precipitation      Colour Change : colour change is associated with transition metal ions. The major cause of the colour in transition metal ions is electronic transition within the d-block level. The colour of light which show, is the colour of light which is reflected by the ion. This change of transition metal ions is common when they form a bond with water or ammonia. It is important to note that zinc does not form coloured ion, this is because zinc has completely filled the d orbital, but zinc is yellow when hot and white when cold. Evolution of gas : This is identified by

Qualitative Analysis of Ammonium Trioxocarbonate (IV)

              Ammonium trioxocarbonate(IV) is an electrovalent compound just like any other ammonium salts. As an electrovalent compound, it has NH + (ammonium ion) as the cation and CO 3 2- (trioxocarbonate IV ion or radical) as the anion.                          (NH 4 ) 2 CO 3   -------    2NH 4 + + CO 3 2- Ammonium trioxocarbonate IV is a white crystal salt and it is very soluble in water like all other ammonium salts. It decomposes on heating to produce ammonium, water and carbon (IV)oxide.                      (NH 4 + ) 2 CO 3   ----------   2NH 3(g) + H 2 O (I) + CO 2(g)          Test for the Cation in Ammonium Trioxocarbonate IV To test the unknown sample, put the sample into a boiling tube, add a base or alkali into the boiling tube and heat gently.   Note: All ammonium salts liberate ammonia when heated with base or alkali.         (NH 4 ) 2 CO 3(s) + 2NaOH (aq) ----------   Na 2 CO 3 (aq) + H 2 O (l) + 2NH 3(g) Test the gas liberated with damp li